Quantum Mechanics 6a – Hydrogen I

Category : Randomness
Quantum Mechanics 6a – Hydrogen Iby wpjljron.Quantum Mechanics 6a – Hydrogen IThe application of Schrödinger’s equation to the hydrogen atom leads to far more than an explanation of the atom’s spectrum. A note on pronunciation: the Gre…

The application of Schrödinger’s equation to the hydrogen atom leads to far more than an explanation of the atom’s spectrum. A note on pronunciation: the Gre…

Author: 

Related Posts

25 Responses

  1. Danny Wray22 June, 2014 at 10:18 pm

    How did you create the 3D Electron cloud you describe at 4:23 ? They look
    too high quality to have been created in Scilab or Matlab?

  2. viascience26 October, 2013 at 10:21 pm

    Thanks. My guideline in making these videos was, “what would I have liked
    to have available when I was learning this stuff?”

  3. viascience21 October, 2013 at 2:37 am

    You are welcome.

  4. nksfeb201225 July, 2013 at 8:56 pm

    excellent explaination

  5. viascience13 July, 2013 at 4:57 am

    You’re very welcome. And, yes, we’ll get to some chemistry.

  6. asa9enaka13 July, 2013 at 1:55 am

    I started watching this playlist 6 hours ago. Could not stop until I
    watched all of it. Appreciate the great effort you put into this. THANK YOU
    VERY MUCH. Will be waiting for the next video. Have a feeling that it may
    tie chemistry into this, and why compounds have their properties.

  7. kneecaps20008 June, 2013 at 10:59 am

    Excellent set of videos. I think these are the best videos for helping non
    physicists really understand the link between the math and the physical.

  8. viascience31 May, 2013 at 2:59 pm

    You’re welcome.

  9. Miki P31 May, 2013 at 11:45 am

    Thank you so much Ozmoroid. Please continue with this remarkable work. You
    are helping many with these videos

  10. Sockheadableful29 April, 2013 at 6:54 pm

    Can you do a series on Statistical Mechanics, your videos are a blessing to
    mankind.

  11. viascience27 April, 2013 at 6:34 am

    I think Greeks do pronounce φ as “fee,” and π as “pee,” χ as “see.” I
    picked this up from my grad advisor, who was from Greece. 😉 Also copy the
    Greek letters into the “Search for a word” box at forvo,com to hear Greeks
    pronounce them.

  12. viascience25 April, 2013 at 5:57 am

    It’s a separate assumption. We’ll cover it in a future video.

  13. viascience17 April, 2013 at 3:17 am

    We will get to the l and m quantum numbers in an upcoming video. They have
    to do with angular momentum.

  14. viascience9 April, 2013 at 1:42 am

    The higher-energy orbitals have regions that overlap the lower energy ones.

  15. viascience9 April, 2013 at 1:40 am

    Nein.

  16. Philip7 April, 2013 at 8:36 pm

    I have a question: when you show the higher energy orbitals and they appear
    to have the smaller versions embedded in them, are those smaller orbitals
    actually the lower energy orbitals or do the higher energy orbitals
    actually have regions that overlap the lower energy ones?

  17. Mike Gale3 April, 2013 at 3:36 am

    Search Youtube for “Solving Schrodinger for a Hydrogen Atom” to see a neat
    way of deriving eigenvalues of E.

  18. Mike Gale3 April, 2013 at 3:03 am

    Are these Bessel functions?

  19. Nat Napoletano30 March, 2013 at 11:21 am

    viascience, thank you so much. This series is spectacular, you have a great
    voice, and your recorded audio is super intelligible.

  20. viascience25 March, 2013 at 1:09 am

    You are correct.

  21. C B24 March, 2013 at 10:10 pm

    excited, not exited?

  22. viascience23 March, 2013 at 4:12 pm

    Yes, the single electron in hydrogen can in principle be exited into any of
    these orbitals.

  23. suniseclipsed22 March, 2013 at 7:32 pm

    Feels a little like a cliffhanger at the end.

  24. Paul Miller22 March, 2013 at 4:48 pm

    i am guessing that the ‘exclusion’ principle will be the next development
    here. The solutions to the single electron/proton Hydrogen atom lays down
    the pattern which all larger atoms must take up? BTW I felt it was
    difficult to follow when jumping from the ‘pyramid’ of solutions to having
    only four on-screen animations at a time. How about having an annotation
    that displays the current total (4,9,16,,,) as a set positions with just
    those on display marked ‘X’ say?

  25. Quintinohthree22 March, 2013 at 4:20 pm

    Much of this I already knew and understood, but it’s never bad to be
    reminded.

Leave a Reply